Question 174854 in PHP Question posted in
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Php – If value contains a given value

I have a php form with one of the fields being a dropdown box that allows multi select, this field is set as a varchar and points to another table for its options, the options are 1 to 8.

I would like to run an if code after adding a record, i can do this if the value is a single value, ie if($value==1), but as this dropdown allows multi select, it is possible for the field to save as 1,2,4,6 or 2,3,4, i.e. any combination of 1 to 8, and separated by a comma.

So what I need to do is get something like if($value….contains 1) {then do something }

Any ideas please

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2

Answers


  1. 0

    You can use explode method

    Then you can use foreach loop

    Example code will look like

    $arrayWithValues = explode($value); 

foreach($arrayWithValues as $selectedOption ) {
  if($selectedOption ==1) {
     // Do smth
    }
}
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  2. 0

    the problem with string_contains is that if value contains a number 15, it would true the condition as it does contain 1 in 15…

    <?php
    $value = explode(",", $value);
    //seperate the value string by a coma and create array
    
    if(gettype(array_search(1, $value)) == 'integer'){
    
    //search the array for '1', if it has it/ returns a number
    //do something
    
    
    }
     ?>
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