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Php – Regex ignore specific string between two strings

So I have a string like this:

test //ita https://example.com lics// test // another // one

I can capture text between 2 "//" strings easy enough like so:

//(.*?)//

Which will return the groups ita https: and test however I’m trying to get it to ignore the cases where there is a "http://" or "https://".

So I’m trying to get it so that it only returns ita https://example.com lics and another.

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3

Answers


  1. 0

    Looks like your on the right track.

    (?<!https?://)//(.*?)(?=(?:s|https?://|$))

    Heres how it works

    (?<!https?://)

    Negative lookbehind assertion to ensure that there is no "http://&quot; or
    "https://&quot; before "//".

    //

    Matches the "//" strings.

    (.*?)

    Captures any text between "//" using a non-greedy match.

    (?=(?:s|https?://|$))

    Positive lookahead assertion to ensure that what follows is either a
    whitespace character, "http://&quot; or "https://&quot;, or the end of the
    string.

    You should post a few string examples to better test but based on what I tried, looks like this works.

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  2. 0

    You can use this regex to match your strings:

    (?<!https:|http:)//s*((?:https?://|(?!//).)*)(?<!s)s*//

    This will match:

    • (?<!https:|http:)// : //, not preceded by https: or http:
    • s* : some amount of whitespace
    • ((?:https?://|(?!//).)+) : capture group 1, some number of either:
      • https?:// : // preceded by https: or http:; or
      • (?!//). : a character which is not the start of //
    • (?<!s)s* : some amount of whitespace, not preceded by whitespace (this prevents capturing any whitespace before the closing // in group 1)
    • // : literal //

    Regex demo on regex101

    The strings you are interested in will be captured in group 1. In PHP:

    $text = 'test //ita https://example.com lics// test // another // one';
$regex = '~(?<!https:|http:)//s*((?:https?://|(?!//).)*)(?<!s)s*//~';
preg_match_all($regex, $text, $matches);
var_export($matches[1]);

    Output:

    array (
  0 => 'ita https://example.com lics',
  1 => 'another',
)

    PHP demo on 3v4l.org

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  3. 0 
    (https?://)(*SKIP)(*F)|//s*((?:(?1)|.)*?)s*//

    I propose this solution with control verbs (*SKIP) and (*F).

    Here’s the regex101 proof and PHP proof

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