Question 226981 in PHP Question posted in
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Php – turn a number based on passed in value to at least 6 digit and max 8 digit

public static function generateReceiptNumber(int $id)
{
     $receipt_number = sprintf('%06d', $id % 100000000);
     return $receipt_number;
}

I am having the above code to help me to transform a passed in $id to a minimum 6 digit and maximum 8 digit number. eg: 000001 – 99999999

But this code has a flaws that when the $id equal to 100000000, it will return me 000000,
how can i enhance the code above to give me 000001 instead?

So and so forth, the $id is the database incremental id

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4

Answers


  1. 0 
    public static function generateReceiptNumber(int $id)
{
    // Handle the special case when $id is 100000000
    if ($id === 100000000) {
        return '000001';
    }

    // Use modulo to limit the ID to the range 0 to 99,999,999
    $limited_id = $id % 100000000;
    
    // Format the limited ID with leading zeros to ensure at least 6 digits
    $receipt_number = sprintf('%06d', $limited_id);
    
    return $receipt_number;
}

    please check this answer if it will help you.

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  2. 0 
    public static function generateReceiptNumber(int $id)
{
     return str_pad((string)$id,6,"0",STR_PAD_LEFT);
}

    This method does not have maximum cap, you can use simply add a condition to do so if really needs

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  3. 0

    How about this:

    function generateReceiptNumber(int $id)
{
    while($id>=100000000)
        $id -= 100000000 - 1;
    return sprintf('%06d', $id);
}
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  4. 0

    Just use the max and min functions to make it an elegant one liner.

    function generateReceiptNumber(int $id){
   return sprintf('%06d', max(1, min($id,100000000) % 100000000));
}

    Live Demo

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