Question 42130 in PHP Question posted in
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Populate Option Value – PHP

I am looking for a way to populate an option value.

<?php for ($i = 1; $i <= 300; $i++) : ?>
    <option value="<?php echo $i; ?>">1.<?php  print $i; ?> AVAX</option>
<?php endfor; ?>

I want for the above code to work something like this. 1.00 - 1.99 after reaching 1.99 I want it to navigate to 2.00 - 2.99 and so forth and onward until the numbers run out. How can I achieve that? The above result returns only 1.300

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2

Answers


  1. 0

    You can set the increment to whatever you want

    <?php for ($i = 1; $i <= 300; $i+=0.01) : ?>
    <option value="<?php echo number_format($i, 2, '.', ''); ?>"><?php  echo number_format($i, 2, '.', ''); ?> AVAX</option>
<?php endfor; ?>

    demo

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  2. 0

    What do you mean by until numbers run out?
    You do realize that numbers are infinite.
    Therefore, I can only assume that you want the options to have the series:
    1.01, 1.02…. 1.99, 2.00, 2.01, 2.02, …. until 10.00.

    If 10 is not the highest number you want to reach, then you can change the end limit of $i in the following code:

    <?php
for ($i = 1; $i <= 10; $i++) { 
   for ($j = 0; $j <= 99; $j++) { 

         $num = "$i." . sprintf('%02d',$j);   // 1.01, 1.02, ...

         echo '<option value="' . $num . '">AVAX</option>';
        
   }
}
?>
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