Question 41040 in PHP Question posted in
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Rounding last decimal place to 0? – PHP

I tried round, ceil and floor, but they do not seem to do what I want (or I dont see the wood for the trees :-))

This is what I want:

1.44 --> 1.40
1.23 --> 1.20
3.50 --> 4.00
2.48 --> 2.50
...

I did not find a way to achieve that. Should be possible?

Thanks!

Tags:

3

Answers


  1. 0

    You can combine round() and number_format():

    For example:

    $number = 1.44;
number_format(round($number, 1), 2, '.', ''); // 1.40
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  2. 0

    I’d use sptrintf to format the number to 1 decimal, then append a 0 behind it:

    sprintf('%0.1f0', $test)

    Test cases:

    <?php

foreach ([ 1.44, 1.23, 3.50, 2.48 ] as $test) {
    $rounded = sprintf('%0.1f0', $test);
    var_dump($rounded);
}

    string(4) "1.40"
string(4) "1.20"
string(4) "3.50"
string(4) "2.50"

    Try it online!

    As string, since trailing 0 on a float are removed by PHP

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  3. 0

    I don’t think there is a native php function already doing what you want. We will need to do it ourself. First by finding the depth of the decimal part, then by rounding depending on depth.

    <?php

function roundToSecondLastDigit(float $number): float{
    $decimal = $number - intval($number);
    $depth = strlen((string) $decimal) - 2;
    
    return round($number, $depth - 1);
}

echo roundToSecondLastDigit(1.44) . "n"; //1.4
echo roundToSecondLastDigit(1.23) . "n"; //1.2
echo roundToSecondLastDigit(3.50) . "n"; //4
echo roundToSecondLastDigit(2.48) . "n"; //2.5

    You can print your number with the precision you want with number_format then.

    echo number_format(roundToSecondLastDigit(2.48), 2, '.', ''); //2.50
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