Question 40710 in PHP Question posted in
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Unable to convert DateTime timestamp to m/d/y format – PHP

So I am using an API and I am getting the following updatedOn response: "UpdatedOn": "/Date(1674542180860+0000)/".

I am using the following code to convert it to m/d/y format:

if (!empty($data->Data->Shipment->UpdatedOn)): 
    $timestamp = preg_replace('/[^0-9+-]/', '', $data->Data->Shipment->UpdatedOn);
    $date = new DateTime("@$timestamp");
    $timestamp = $date->getTimestamp();
    $parse_date = date('m/d/Y', $timestamp);
    echo '<span>' . $parse_date . '</span>';
endif;

The issue is that it’s not outputting properly, so I need some help – Here is the output that I am receiving:

02/17/55034

I would like to output it in the following format: January 12th, 2023.

Could anyone help me with my code?

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2

Answers


  1. 0

    In our decade timestamp is a 10 digit number
    So this nember => "1674542180860" must be devide to 1000,
    And if these two numbers "1674542180860" and "0000" must be added together, we should explod this string and sum two number,
    I suggest you try this:

    if (!empty($data->Data->Shipment->UpdatedOn)){
            $timestamp = preg_replace('/[^0-9+-]/', '', $data->Data->Shipment->UpdatedOn);
            $timestamp = explode('+',$timestamp);
            $timestamp = (int)$timestamp[0] + (int)$timestamp[1];
            $timestamp = (int)($timestamp/1000);
            $parse_date = date('F dth Y', $timestamp);
            echo '<span>' . $parse_date . '</span>';
        }

    This is your favorite format to show date => "F dth Y"

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  2. 0 
    if(!empty($data->Data->Shipment->UpdatedOn)){
    $parse_date = date('M d, Y', strtotime($data->Data->Shipment->UpdatedOn));
    echo '<span>' . $parse_date . '</span>';
}
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