I have data in my PHPMYADMIN in a few columns and rows.
Via PHP I read the Data out of my SQL Table and print it into a table.
The last of my table is a action button. So the whole table is a echo and within the table there’s a html form in the last , but only with a submit button (input type=”hidden”) but the value should be the “id” out of my SQL table.
Here’s the problem. How can I get the id of one row into the value of an input field? . $row[“id”]. doesn’t work. How can I fix this problem?
This is for a Website where the user can vote a table row up and then with the html form it is sending via http post to another page where it overrides the current number in the database with +1
$sql = "SELECT * FROM votingpoll ORDER BY votecount DESC";
$result = $conn->query($sql);
echo "$id";
echo "<table>";
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "<tr>
<td>
<form action='vote.php' method='post'>
<input type='text' name='id' value='$id'>
<input type='submit' value='VOTE'>
</form>
</td>
</tr>";
}
} else {
echo "0 results";
}
Thank you!!!
2
Answers
You can do
$row[id]
i.e. leave the quotes off when the array reference is used inside a double quoted string.Or if you prefer you could use
It looks like you aren’t setting
$id
anywhere. Try setting it from the results like$id = $row["id"];
Full example: