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How do I get mysql user_id from php session? – Phpmyadmin

In my code I use $user_id = $_SESSION[“USER_ID”]; to get the users id that is valid. If I use echo function in PHP it displays the correct id but when I try to use it in query it says it is undefined.

I am using XAMPP with:
PHP 7.1.27 , 7.2.16 , 7.3.3
Apache 2.4.38
MariaDB 10.1.38
Perl 5.16.3
OpenSSL 1.0.2r (UNIX only)
phpMyAdmin 4.8.5

$user_id = $_SESSION["USER_ID"];

// Funkcija prebere oglase iz baze in vrne polje objektov

function get_oglasi(){
    global $conn;
    $query = "SELECT * FROM ads WHERE user_id= echo '$user_id'; ";
    $res = $conn->query($query);
    $oglasi = array();
    while($oglas = $res->fetch_object()){
        array_push($oglasi, $oglas);
    }
    return $oglasi;
}

I expect the output of $user_id = 17 and I get error that it is undefined. But if I try <p>Opis: <?php echo $user_id;?></p> I get correct number.

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3

Answers


  1. 0

    You need to make $user_id as global global $user_id; because You are using in function and it is define outside function.

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  2. 0

    Or pass a parameter to a function then you will get the id inside the function
    function get_oglasi($id)

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  3. 0

    In php you are not able read variable without Global declaring or send to function parameter.
    Please set this session user_id like below code 

     $user_id = $_SESSION["USER_ID"];

 function get_oglasi(){

 $user_id=$GLOBALS['user_id'];

 global $conn;
 $query = "SELECT * FROM ads WHERE user_id='$user_id'; ";
 $res = $conn->query($query);
 $oglasi = array();
 while($oglas = $res->fetch_object()){
    array_push($oglasi, $oglas);
 }
return $oglasi;
}

    Hopefully that will help you.

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