receiving error message "no such element: Unable to locate element" when trying to find an element with xpath - Phpmyadmin

RobertDL
September 11, 2019
176 views
3 votes
3 Answers

Access to a hosted MariaDB using a connector is not allowed by the provider. I therefore try to export some tables using a Python script with Selenium. I do not manage to find / click the export button of phpMyAdmin.

I try to locate the button using its XPATH, obtained with the Chrome browser.
I updated Chrome, the driver, Selenium to the latest versions. Attempted to make the driver wait:

(WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//div[@class='navigationbar']/ul[@id='topmenu']//li//img[@title='Exporteren']"))).click())

The problem is that for some reason, the button cannot be found by the driver.
I tried to search by xpath, class, css, … without success.
I do not find any frame in the html code.
Below some html code (that seems to get interpreted in the question…)

HTML:

    <div class="navigationbar"><ul id="topmenu"  class="resizable-menu">
    <li>
            <a href="server_status.php" class="tab">
            <img src="themes/dot.gif" title="Status" alt="Status" class="icon ic_s_status" />&nbsp;Status
            </a>
        </li>
    <li>
            <a href="server_export.php" class="tab">
            <img src="themes/dot.gif" title="Exporteren" alt="Exporteren" class="icon ic_b_export" />&nbsp;Exporteren
            </a>
        </li>
    <li>

Code trials:

python
    btnexp = driver.find_element_by_xpath("//*[@id='topmenu']/li[4]/a/img")
    btnexp.click()

Error message:

no such element: Unable to locate element: {"method":"xpath","selector":"//*[@id='topmenu']/li[4]/a/img"}

Answers

Chosen as BEST ANSWER
- RobertDL
- September 13, 2019 at 10:19 am
- 0 votes
0
Activation of the most recent window: driver.switch_to_window(driver.window_handles[-1])

(Edit)

- JeffreyB
- September 11, 2019 at 1:18 pm
- 0 votes
0
Have you tried locating the element by Class Name?
```
content = driver.find_element_by_class_name('icon ic_s_status')
content = driver.find_element_by_class_name('icon ic_b_export')
```
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- undetectedSelenium
- September 11, 2019 at 2:00 pm
- 0 votes
0
To click() on the element with text as Exporteren you have to induce WebDriverWait for the element_to_be_clickable() and you can use either of the following Locator Strategies:
- Using CSS_SELECTOR:
```
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "div.navigationbar > ul#topmenu li img[title='Exporteren']"))).click()
```
- Using XPATH:
```
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//div[@class='navigationbar']/ul[@id='topmenu']//li//img[@title='Exporteren']"))).click()
```
- Note : You have to add the following imports :
```
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
```
- You can find a couple of relevant discussions in:
  - Selenium “selenium.common.exceptions.NoSuchElementException” when using Chrome
  - selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element while trying to click Next button with selenium
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