Question 199152 in PostgreSQL Question posted in
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Postgresql – Can someone help me resolve an sql syntax error on pgadmin while creating a function?

First Attempt –

CREATE FUNCTION rental_quarter (rental_date TIMESTAMP)
RETURNS VARCHAR(7)
BEGIN 
 IF MONTH(rental_date) BETWEEN 1 AND 3 THEN RETURN YEAR(rental_date)+ ”Q1”;
 ELSE IF MONTH(rental_date) BETWEEN 4 AND 6 THEN RETURN YEAR(rental_date)+ ”Q2” ; 
 ELSE IF MONTH(rental_date) BETWEEN 7 AND 9 THEN RETURN YEAR(rental_date)+ ”Q3”;
 ELSE IF MONTH(rental_date) BETWEEN 10 AND 12 THEN RETURN YEAR(rental_date)+ ”Q4”;
 ELSE RETURN NULL ;
END IF;
END;

Latest try Code and Error

EDIT Suggested fix error #1

I am new to sql and have been stuck on this a few hours . I am trying to create a rental_quarter(rental_date) function that turns the time stamped date format (without timezone) into year + quarter. I have no Idea what I am doing wrong. I have tried using AS, DECLARE, SET AS. I’ve done every variation of semicolons. It has to be a user defined function to meet project requirements. Please help.

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2

Answers


  1. 0

    This is with minimum changes I think:

    CREATE FUNCTION rental_quarter (rental_date TIMESTAMP)
RETURNS VARCHAR(7) AS
$BODY$
BEGIN 
 IF MONTH(rental_date) BETWEEN 1 AND 3 THEN RETURN YEAR(rental_date)+ ”Q1”;
 ELSIF MONTH(rental_date) BETWEEN 4 AND 6 THEN RETURN YEAR(rental_date)+ ”Q2”;  
 ELSIF MONTH(rental_date) BETWEEN 7 AND 9 THEN RETURN YEAR(rental_date)+ ”Q3”;
 ELSIF MONTH(rental_date) BETWEEN 10 AND 12 THEN RETURN YEAR(rental_date)+ ”Q4”;
 ELSE RETURN NULL ;
 END IF;
END;
$BODY$
LANGUAGE PLPGSQL;
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  2. 0

    There is already a function for this, to_char(), you don’t have write one yourself:

    SELECT to_char('2023-08-01'::timestamp, 'YYYY"Q"Q');

    Result: 2023Q3

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