Question 22403 in SEO Question posted in
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Get definite values from string – SEO

I need to get the values of ‘name’ from such string

[{'self': 'https://jira.zxz.su/rest/api/2/component/11207132',
  'id': '11207',    
  'name': 'SEO'},    
 {'self': 'https://jira.zxz.su/rest/api/2/component/12200123',    
  'id': '12200',    
  'name': 'НКК'}]

I want to get an output like 'SEO','HKK' all in one string.

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5

Answers


  1. 0

    This should work:

    data = [{'self': 'https://jira.zxz.su/rest/api/2/component/11207132',
  'id': '11207',    
  'name': 'SEO'},    
 {'self': 'https://jira.zxz.su/rest/api/2/component/12200123',    
  'id': '12200',    
  'name': 'НКК'}]

print(','.join([f"'{x['name']}'" for x in data]))

    Output:

    "'SEO','НКК'"

    Explanation:
    The list comprehension creates a flat list comprised of values corresponding to the name key for every dictionary in data. Then we simply wrap those elements in quotes and join them in a comma-separated string.

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  2. 0

    You have a list of dictionaries. All you need to do is to iterate over the dictionaries and to keep the name key of each one of them:

    entities = [{'self': 'https://jira.zxz.su/rest/api/2/component/11207132', 'id': '11207', 'name': 'SEO'},
            {'self': 'https://jira.zxz.su/rest/api/2/component/12200123', 'id': '12200', 'name': 'НКК'}]

result = []
for entity in entities:
    result.append(entity['name'])

print(result)

    Output:

    ['SEO', 'НКК']
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  3. 0

    If your input is not an array or dictionary, but a string you can not directly access the data. You can use json:

    import json
def get_names(components: str):
    # prevent error: json.decoder.JSONDecodeError: Expecting property name enclosed in double quotes
    components = components.replace(''', '"')
    # convert string to json
    components = json.loads(components)
    # create empty list
    names = []
    # iterate through components
    for component in components:
        # append name to list
        names.append(component['name'])
    # return list
    return names

s = """[{'self': 'https://jira.zxz.su/rest/api/2/component/11207132',
  'id': '11207',    
  'name': 'SEO'},    
 {'self': 'https://jira.zxz.su/rest/api/2/component/12200123',    
  'id': '12200',    
  'name': 'НКК'}]"""
print(get_names(s))

    Output:

    ['SEO', 'НКК']

    To get your requested Output you can do:

    print(', '.join(["'"+i+"'" for i in get_names(s)]))

    This will give you:

    'SEO', 'НКК'
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  4. 0

    Depends on how you want your name data stored, but something like this will work:

    dicts = [
{'self': 'https://jira.zxz.su/rest/api/2/component/11207132',
 'id': '11207',
 'name': 'SEO'},
{'self': 'https://jira.zxz.su/rest/api/2/component/12200123',
 'id': '12200',
 'name': 'НКК'}
]

names_only = [i['name'] for i in dicts]
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  5. 0

    This should extract and format the names as you indicate:

    dx = [{'self': 'https://jira.zxz.su/rest/api/2/component/11207132',
       'id': '11207',    
       'name': 'SEO'},    
      {'self': 'https://jira.zxz.su/rest/api/2/component/12200123',    
       'id': '12200',    
       'name': 'НКК'}] 

names = ", ".join(["'{}'".format(item.get('name')) for item in dx])
print(names)

    Putting this into the REPL shows:

    >>> print(names)
'SEO', 'НКК'
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