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how can I split a list and print it in separate lines? – Telegram

Hi this is my code for Telegram bot,I have a list that fills by names.
the bot add usernames to list and reply it as a list
I want to reply every name in seperate lines

list = []
txt = str(list)


def msg_filter(bot , update):
wordsp = ["man"," miam"]
wordsn = ['nemiam','nistam','na']

if len(list) <=15:

    if any (i in update.message.text for i in wordsp):

        if "{}".format(update.message.from_user.first_name) not in list:
            list.append("{}".format(update.message.from_user.first_name))
            bot.send_message(chat_id = update.message.chat_id , text = "{}".format(list))

I have this in output : ['username1','username2','username3']

but expect this:
Tags:

4

Answers


  1. 0

    text=”[{}]”.format(“n”.join(lst))

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  2. 0

    If you want to output the list new-line separated you can use #join and use the newline-character (n) as separator for your list entries.

    For example:

    bot.send_message(chat_id = update.message.chat_id , text = "n".join(list))

    which will output:

    username1
username2
username3

    If you explicitly want the [ & ] outputed as well, you can use format to add them:

    text = "[n{}n]".format("n".join(list))
bot.send_message(chat_id = update.message.chat_id , text = text)
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  3. 0

    you could use: 

     print('n'.join(list))
 # please do not name your list "list", list is a build-in function !!!
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  4. 0

    If you need exact this result without any quotes:

        [username1
    usernam2
    username3]

    Try this simple solution:

        print(f'[{list_[0]}')
    for l in list_[1:-2]:
        print(l)
    print(f'{list_[-1]}]')

    where list_ = [‘username1′,’username2′,’username3’]

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