Question 59800 in Telegram API Question posted in
A comprehensive official documentation can be found here.

How to split the interface passed to the method – Telegram API

I use this library tucnak/telebot to build a telegram bot.

Method b.Handle() have two parameters such as Handle(endpoint interface{}, handler interface{})`.

Here is the code i use for a starter

func main() {
    b, err := tb.NewBot(tb.Settings{
        Token:  "TOKEN_HERE",
        Poller: &tb.LongPoller{Timeout: 10 * time.Second},
    })

    if err != nil {
        log.Fatal(err)
        return
    }
    // i want to split this(interface)
    b.Handle("/hello", func(m *tb.Message) {
        b.Send(m.Sender, "Hello World!")
    })

    b.Start()
}

Here is what I have tried to compile :

func main() {
    b, err := tb.NewBot(tb.Settings{
        Token:  "TOKEN_HERE",
        Poller: &tb.LongPoller{Timeout: 10 * time.Second},
    })

    if err != nil {
        log.Fatal(err)
        return
    }
                    
    b.Handle("/hello", handleHello(b))

    b.Start()
}

func handleHello(b *tb.Bot) {
        b.Send(m.Sender, "Hello World!")
}

I have an error with this code : undefined m, in m.Sender() and I can’t use m as a parameter for that function call, because of the same error. I don’t understand where that m comes from.

Tags:

2

Answers


  1. 0

    As you can see hello handler takes a parameter called m here.

    b.Handle("/hello", func(m *tb.Message) {

    so you should return a function that takes the same parameter.

    func handleHello(b *tb.Bot) func(m *tb.Message) {
    return func(m *tb.Message) {
        b.Send(m.Sender, "Hello World!")
    }
}
    Login or Signup to reply.
  2. 0

    The bot responsibility is to listen some sockets, whatever, and calls your function handlers when a message arrives on the associated path handler.

    Thus, you should not try to call your handlers like in b.Handle("/hello", handleHello(b)). Instead pass the function handler to the bot b.Handle("/hello", handleHello). Let the bot call that function with the new message as a parameter like in func(m *tb.Message).

    To retain a reference to b, you can proceed as described by Sinan Coment. Write a function that takes in parameter the bot and returns a function that receives the message as a parameter.

    The bot instance b acts as a muxer, you can re use that terminology to improve the meaning of your code.

    A muxer is defined as [...] a request multiplexer. It matches the URL of each incoming request against a list of registered patterns and calls the handler for the pattern that most closely matches the URL.

    Though, I want to suggest you to wrap that instance of telebot.Bot into a type that defines message handlers as methods.

    package main

import (
    "log"
    "time"

    tb "gopkg.in/tucnak/telebot.v2"
)

func main() {
    mux, err := tb.NewBot(tb.Settings{
        Token:  "TOKEN_HERE",
        Poller: &tb.LongPoller{Timeout: 10 * time.Second},
    })

    if err != nil {
        log.Fatal(err)
        return
    }

    bot := botHandlers{Bot: mux}

    mux.Handle("/hello", bot.handleHello)

    mux.Start()
}

type botHandlers struct {
    *tb.Bot
}

func (b botHandlers) handleHello(m *tb.Message) {
    b.Send(m.Sender, "Hello World!")
}

    https://play.golang.org/p/6ng6WSIp8Er

    Login or Signup to reply.
Please signup or login to give your own answer.

Back To Top
Search