Question 59666 in Telegram API Question posted in
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My telegram auto message bot is working one time, how can I loop it? – Telegram API

hi i made a telegram auto-messaging bot using python but it only sends messages when i run it i need your help on how to loop it.

import sys
from telethon import TelegramClient
import time 
import datetime
starttime = time.time()

api_id = #api id
api_hash = '#api hash'

groups = ['#groups ']

failcount = 0;

while True:
    with TelegramClient('anon', api_id, api_hash) as client:
        for x in groups:
            try:
                client.loop.run_until_complete(client.send_message(x, '#message'))
            except:
                print(x, sys.exc_info()[0])
                failcount == 1
    print(datetime.datetime.now(), str(failcount/len(groups) * 100) + '%')
    time.sleep(10800 - ((time.time()- starttime) % 10800))
Tags:

3

Answers


  1. 0

    Well i dont know much about that but if the last print is the messsage you can always try putting it into the loop.

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  2. 0

    that’s obvious lmao delete all this and read the docs.

    you start a file like this:

    import things you need

    client = TelegramClient("session name", api_id, api_hash)

////////// code


client.run_until_disconnected()

    to send a message use

    @client.send_message('username or id', 'message')

    oh and failcount should be += 1 (failcount = failcount + 1)

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  3. 0

    You actually only need to make login once. Here is an working example:

    # Telethon
from telethon import TelegramClient, events, utils
import asyncio
import logging
import sys
logging.basicConfig(format='[%(levelname) 5s/%(asctime)s] %(name)s: %(message)s',
                    level=logging.WARNING)

api_id = '#api id'
api_hash = '#api hash'


client = TelegramClient('my_app', api_id, api_hash)

async def main():
    # Sending messages for myself
    i = 0;
    while True:
        await asyncio.sleep(1);
        await client.send_message("me", f'Message - {i}')
        i += 1;
       

with client:
    client.loop.run_until_complete(main())

    The loop above will send messages forever, but, you can add if else to break the loop.

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