I am wanting to create a bot for telegram and a web application from which I can edit and store the commands for said bot. The problem arises when I deploy in heroku, since I cannot run the bot and the web application at the same time. I think I am having problems with the webhook. This is my code.
app.py
import os
import sys
import telegram
from telegram.ext import Updater, updater
from telegram.ext.commandhandler import CommandHandler
from resources.commands import *
from flask import Flask, render_template, request
token = "Telegram bot token"
heroku_app_name = "Heroku app name"
bot = telegram.Bot(token= token)
app=Flask(__name__)
updater = Updater(bot.token, use_context= True)
@app.route('/home')
def home():
return render_template('home.html')
@app.route('/')
def webhook():
updater.start_webhook(listen="0.0.0.0",
port=int(os.environ.get('PORT', 5000)),
url_path=token,
webhook_url="https://{}.herokuapp.com/{}".format(os.environ.get("HEROKU_APP_NAME"), token))
return "!", 200
if __name__ == '__main__':
webhook()
app.run(host='0.0.0.0', port=int(os.environ.get('PORT', 5000)))
dp = updater.dispatcher
dp.add_handler(CommandHandler("hello", hellothere))
def hellothere(update, context):
update.message.reply_text("Hello There!!")
home.html
<!DOCTYPE html>
<html lang="en" dir="ltr">
<head>
<meta charset="utf-8">
<link rel="icon" href="data:,">
<meta name="viewport" content="width=device-width,initial-scale=1">
<title>Bot</title>
</head>
<body>
<h1>Hello world!!</h1>
</body>
</html>
Procfile
web: python app.py
Log
2021-10-27T16:49:56.962690+00:00 heroku[web.1]: Starting process with command `python app.py`
2021-10-27T16:49:59.445699+00:00 app[web.1]: 2021-10-27 16:49:59,445 - apscheduler.scheduler - INFO - Scheduler started,
2021-10-27T16:49:59.800346+00:00 app[web.1]: * Serving Flask app 'app' (lazy loading)
2021-10-27T16:49:59.800372+00:00 app[web.1]: * Environment: production
2021-10-27T16:49:59.800373+00:00 app[web.1]: WARNING: This is a development server. Do not use it in a production deployment.
2021-10-27T16:49:59.800387+00:00 app[web.1]: Use a production WSGI server instead.
2021-10-27T16:49:59.800399+00:00 app[web.1]: * Debug mode: on
2021-10-27T16:49:59.817520+00:00 app[web.1]: Traceback (most recent call last):
2021-10-27T16:49:59.817521+00:00 app[web.1]: File "/app/app.py", line 401, in <module>
2021-10-27T16:49:59.817724+00:00 app[web.1]: app.run(debug=True, host='0.0.0.0', port=int(os.environ.get('PORT', 5000)))
2021-10-27T16:49:59.817727+00:00 app[web.1]: File "/app/.heroku/python/lib/python3.9/site-packages/flask/app.py", line 920, in run
2021-10-27T16:49:59.817951+00:00 app[web.1]: run_simple(t.cast(str, host), port, self, **options)
2021-10-27T16:49:59.817960+00:00 app[web.1]: File "/app/.heroku/python/lib/python3.9/site-packages/werkzeug/serving.py", line 984, in run_simple
2021-10-27T16:49:59.818196+00:00 app[web.1]: s.bind(server_address)
2021-10-27T16:49:59.818260+00:00 app[web.1]: OSError: [Errno 98] Address already in use
2021-10-27T16:50:00.329639+00:00 heroku[web.1]: State changed from starting to up
2021-10-27T16:50:11.000000+00:00 app[api]: Build succeeded
Any idea?
2
Answers
comment out the line
app.run(host=’0.0.0.0′, port=int(os.environ.get(‘PORT’, 5000)))
you will not have a /home handler
but the webhook will probably work listening on the Heroku supplied port
You cannot have 2 processes on the same port (see error) and you cannot use 2 different ports on the same Heroku Dyno.
You could use the Flask APP as REST frontend and, instead of the Telegram Webhook, you can use the
pollingapproach (which does not need to bind a port)