Question 59336 in Telegram API Question posted in
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Writing custom url model field in Django – Telegram API

I am creating one model called Profile in which i have to add a url field for telegram profile. It takes username as input, but in output it should look like this: https://t.me/{username}.
How I can create custom model field for this problem. Thanks by the way

My expectation is that, you only enter username, but in output it comes with prefix https://t.me/ and full url path will be https://t.me/{username}

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2

Answers


  1. 0

    create a function under your model and use it in the template:

    def get_tg_link(self):
    return f"https://t.me/{self.telegram_username}"

    or override save function under your model

    def save(self, *args, **kwargs):
    self.telegram_profile = f"https://t.me/{self.tg_username}"
    super().save(*args, **kwargs)
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  2. 0

    Create a property function in your profile model.

    @property
def get_telegram_link(self):
    return f"https://t.me/{self.telegram_username}"

    When accessing the model link on your template or code use:

    profile_instance.get_telegram_link()
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