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finding words from an array, in a string – Twitter API

I’m using a twitter API and are scanning tweets to see if they contain a word which is in an array named ‘special’. The following code appears to work fine, but only indicates when it finds a match. How do I also get it to show both the particular word that matched, and the string that the word was contained in?

if any(word in tweet.body for word in special):
                print "match found"

What I’d like is something along the lines of “the word BOB was found in the tweet ‘I am BOB'”

Cheers

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3

Answers


  1. 0

    This code will print all matched words for given tweet.

    def find_words_in_tweet(tweet, words):
    return [word for word in words if word in tweet]

special = ['your', 'words']
for tweet in tweets:
    words = find_words_in_tweet(tweet.body, special)
    print "Matched words: {words} in tweet: {tweet}.".format(
        words=words.join(', '), tweet=tweet.body
    )
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  2. 0 
    for word in special:
    if word in tweet.body:
        print "Matched {0}. In string: {1}.".format(word, tweet.body)

    Updated snippet as per request in comment

    import re

word = 'one'
result = re.search(r'b'+ word + r'b', 'phone hello')
if result:
    print "Found!"
else:
    print "No Match!!!"

    Result:

    No Match!!!
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  3. 0

    Use regx appropriately

    import re

for word in special:
    reg_object = re.search(word, tweet_body, re.IGNORECASE)
    if reg_object:
        print(reg_object.group(), word) # this will get you the exact string 
        # That matched in the tweet body and your key string.

    use re.IGNORECASE only if you need case insensitive search.

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