I have these form inputs, where I have an add button which creates new rows.
My problem is the info button – which is a bootstrap popover. If I add more lines, and click the info button for the new row then the 1st info button opens not the info button for the new row.
How can I fix this?
I have tried this Jsfiddle
var dataList = $('.products');
var jsonOptions = [{
"product": "11111",
"description": "description 1",
"labels": [{
"version": "01",
"quantity": 500
}, {
"version": "02",
"quantity": 800
}, ]
}, {
"product": "22222",
"description": "description 2",
"labels": [{
"version": "01",
"quantity": 900
}, {
"version": "02",
"quantity": 100
}, ]
}, {
"product": "33333",
"description": "description 3",
"labels": [{
"version": "01",
"quantity": 200
}, {
"version": "02",
"quantity": 4300
}, ]
}];
jsonOptions.forEach(function(item) {
var option = '<option value="' + item.product + '">' + item.description + '</option>';
dataList.append(option);
});
$(function() {
$('body').on('input', '.product,.products', function() {
var i = this.value;
var description = "";
var productsInBox = 0;
var text = "";
var version = '';
var quantity = '';
jsonOptions.forEach(function(a) {
if (a.product == i) {
description = a.description;
productsInBox = a.productsInBox;
text = a.labels
a.labels.forEach(function(el) {
version += el.version + " ";
quantity += el.quantity + " ";
});
}
});
$('[data-toggle="popover"]').attr('data-content', "versions are: " + version + ' and quantity are: ' + quantity).data('bs.popover').setContent();
$(this).closest('.form-group').find('.description').val(description);
$(this).closest('.form-group').find('.mytext').val(description);
});
});
var counter = 0;
$('#form1')
.on('click', '.addButtonDED', function() {
counter++;
var $template = $('.form-group').slice(-1).clone(true, true).find('input').val('').end()
.find('.addButtonDED').removeClass('addButtonDED').addClass('removeButtonDED').end()
.find('[name^="product-"]').attr('name', 'product-' + counter).end()
.find('[name^="description-"]').attr('name', 'description-' + counter).end()
.find('i').removeClass('fa-plus').addClass('fa-minus').end();
$template.insertAfter('.form-group:last');
})
// Remove button click handler
.on('click', '.removeButtonDED', function() {
var $row = $('.form-group').slice(-1);
counter--;
$row.remove();
});
$('[data-toggle="popover"]').popover();
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<link href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css" rel="stylesheet" />
<link href="https://maxcdn.bootstrapcdn.com/font-awesome/4.5.0/css/font-awesome.min.css" rel="stylesheet" />
<script src="https://cdnjs.cloudflare.com/ajax/libs/twitter-bootstrap/3.3.7/js/bootstrap.min.js"></script>
<form id="form1" method="post" class="form-horizontal" role="form">
<fieldset>
<div class="form-group">
<div class="col-sm-2">
<input type="text" list="products" class="form-control product" name="product[]" />
<datalist id="products" class="products"></datalist>
</div>
<div class="col-sm-3">
<input id="" type="text" class="form-control description" name=" description[]" />
</div>
<div class="col-sm-1">
<button type="button" class="btn btn-default addButtonDED"><i class="fa fa-plus"></i></button>
</div>
<div class="col-sm-3" style="margin-left: 10px;">
<button type="button" class="btn btn-info btn-group-sm mytext" data-toggle="popover" data-content="text to change to like: version 01 has 500 "><i class="fa fa-info"></i></button>
</div>
</div>
</fieldset>
</form>
4
Answers
you can use
popover
settings for defineselector
like:update fiddle here
Instead of :
You should try this :
Change this :
$('[data-toggle="popover"]').popover();
To this:
It requires double click tho to open the popover.
Try replacing
with