Question 112286 in Ubuntu Question posted in
The official Ubuntu documentation can be found here.

How to replace certain position after match using sed in Ubuntu?

I have a line I want to replace such as

'baseurl' => 'https://231.231.231.231'

But I only want it to replace the https://231.231.231.231 part.

Basically I want it to be

'baseurl' => 'myvaluehere'

I have tried sudo sed -i "s|'baseurl'|${value1}|g" file.php

How do I replace after certain characters after ‘baseurl’ is matched?

Tags:

2

Answers


  1. 0

    Using sed

    $ sed -E "/(baseurl'[^']*')[^']*/s//1myvaluehere/" input_file
'baseurl' => 'myvaluehere'
    Login or Signup to reply.
  2. 0

    Here is the way you can achieve it:

    1. find the match
    2. exclude it
    3. find the next pattern and replace it

    And here is a version since have not used sed so much:

    perl -lpe "s/'baseurl' => K'http[^ ]+/'XYZ'/g" <<< "'baseurl' => 'https://231.231.231.231'"
'baseurl' => 'XYZ'
    • 'baseurl' => find the match
    • K exclude it (= ignore it for substitution)
    • 'http[^ ]+ match this part and replace it — the assumption is that there is no space in the url
    • 'XYZ'
    • <<< is a feature and means String Here which provides input for perl , or:
      • echo "string" | perl -lpe ..., also can be
      • perl -lne ... file.txt

    Since we use double quotes " in we can use variables as well:

    VAR=XXYYZZ
perl -lpe "s/'baseurl' => K'http[^ ]+/$VAR'/g" <<< "'baseurl' => 'https://231.231.231.231'"
'baseurl' => XXYYZZ'
    Login or Signup to reply.
Please signup or login to give your own answer.

Back To Top
Search