Question 37366 in Ubuntu Question posted in
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Using subprocess.Popen messing Ubuntu terminal output

Using subprocess.Popen messing Ubuntu terminal output

import subprocess
import time

subprocess.Popen("sudo ./agt_internal", shell=True, cwd="/home/boblittle/AGT/")
time.sleep(10)

for i in range(10):
    print('Good Morning America')

The terminal output is messed up. Any suggestions?
enter image description here

def start_agt_pmlog():
    command = 'sudo ./agt_internal -unilog=PM'
    args = shlex.split(command)
    print(f'Starts AGT PMLog')
    subprocess.Popen(args, shell=False, cwd="/home/boblittle/AGT/", stdout=subprocess.PIPE, stderr=subprocess.PIPE)

I chaged the code with a suggested solution by adding the function above. It didn’t help.

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2

Answers


  1. Chosen as BEST ANSWER
    0

    Found a simple solution. Adding subprocess.run("reset", shell=True). It clears the terminal but it's good enough for me.

    import subprocess
import time

subprocess.Popen("sudo ./agt_internal", shell=True, cwd="/home/boblittle/AGT/")
time.sleep(10)

subprocess.run("reset", shell=True)
for i in range(10):
    print('Good Morning America')

  2. 0

    You should use shlex.split(), you have a missing double quote and also you should pass the stdout and stderr parameters to subprocess.Pope to avoid your terminal messing up.

    import subprocess
import time
import shlex

command = "sudo ./agt_internal"
args = shlex.split(command)

subprocess.Popen(args, shell=False, cwd="/home/boblittle/AGT/", stdout=subprocess.PIPE, stderr=subprocess.PIPE)
time.sleep(10)

for i in range(10):
    print('Good Morning America')
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