Question 134399 in Visual Studio Code Question posted in
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Visual Studio Code – With C++20, function with reference argument doesn't accept a tempoary object

inline string& rtirm(string& s)
{
    s.erase(s.find_last_not_of(' ') + 1);
    return s;
}

const char* buf = " abc ";
string s_trim = rtirm(string(buf));

This code has been working well until I upgraded visual studio to 2022 and with C++20.

Error C2664 ‘std::string &rtirm(std::string &)’: cannot convert
argument 1 from ‘std::string’ to ‘std::string &’

I clearly understand the reason — a reference can’t refer to a tempoary object.
But this make the code more complicated. Do I have to define a variable before calling rtirm?

string temp{buf};
string s_trim = rtirm(temp);
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2

Answers


  1. Chosen as BEST ANSWER
    0 
    inline string& rtirm(string& s)
{
    s.erase(s.find_last_not_of(' ') + 1);
    return s;
}

inline string rtrim(string&& s)
{
    s.erase(s.find_last_not_of(' ') + 1);
    return s;
}

void test(){
    const char* buf = "    abc    ";
    string sTemp{ buf };
    rtrim(sTemp);
    
    string s_trim = rtrim(string(buf));
}

    I prefer this, adding a rvalue-reference version, that makes both reference and rvalue-reference arguments working.


  2. 0

    yes, you have to define a variable and then call rtrim using it instead of temporary object.

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