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I am running a query loop and want that ‘if‘ the post has a featured image, it needs to be inside a <figure> tag. But the featured image’s <img> tag is appearing before the <figure> tag. What could be the reason?

        foreach($posts as $post){
            setup_postdata($post);
            

            echo '<article class="pet_post">';
                if(has_post_thumbnail()) { echo '<figure class="post_thumbnail">'. the_post_thumbnail('full') . '</figure>'; };
                echo '<h1 class="post_title">'. get_the_title() . '</h1>';
                echo '<p class="pet_seller">'. get_the_content() . '</p>';
                echo '<form method="POST">';
                    echo '<input type="hidden" name="post-id" value="'. get_the_ID() . '">';
                    echo '<button type="submit" name="delete-post">Delete this post</button>';
                echo '</form>';   
            echo '</article>';
        };

The problem can be better understood with this image:
enter image description here

2

Answers


  1. It’s because you’re using the_post_thumbnail function which echo the image by default which happens sooner than echoing out the figure tag.

    Replace

    echo '<figure class="post_thumbnail">'. the_post_thumbnail('full') . '</figure>';
    

    with

    echo '<figure class="post_thumbnail"><img src="' . get_the_post_thumbnail_url(get_the_ID(), "full") . '"></figure>';
    
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  2. I believe this approach is also acceptable.

    <figure class="post_thumbnail">
        <?php if(has_post_thumbnail()) { echo the_post_thumbnail('full'); }; ?>
    </figure>
    
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