Question 30265 in Wordpress Question posted in
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How to call is_user_logged_in() within JavaScript – WordPress

I’m trying to check if the user is logged in or not (in the header of the page), so I can decide if I count that user in Google Analytics or not.
All I need is a true or false (0/1) from that function, but I am not sure how to properly call it within JS.

You can ignore the part within the IF blocks, it’s just a dataLayer push so I can later use the value for triggering the Google Analytics tags accordingly.

So far I tried these options but without luck:

   var logintemp=0;
   logintemp=<?php echo is_user_logged_in() ?> ;

       if (logintemp) {
       window.dataLayer = window.dataLayer || [];
       window.dataLayer.push({
       'userLoggedIn' : '1'
       });} 
       
       else {
       window.dataLayer = window.dataLayer || [];
       window.dataLayer.push({
       'userLoggedIn' : '0'
       });}
</script>

<script type="text/javascript">
        if ('<?php is_user_logged_in(); ?>') {
        window.dataLayer = window.dataLayer || [];
        window.dataLayer.push({
        'userLoggedIn' : '1'
        });} 
        
        else {
        window.dataLayer = window.dataLayer || [];
        window.dataLayer.push({
        'userLoggedIn' : '0'
        });}
</script>```
Tags:

3

Answers


  1. Chosen as BEST ANSWER
    0

    @Clarus Dignus at the Wordpress-Org forum offered a nice solution via a plugin that makes sure the header code is executed in the header. He first asked me to execute this, to confirm everything is working:

    <?php
if ( is_user_logged_in() ) {
    echo 'Welcome, registered user!';
} else {
    echo 'Welcome, visitor!';
}
?>

    Then I used his solution to do the dataLayer push and works perfectly!:

    <?php
if ( is_user_logged_in() ) {
?>
<script>
//Your JavaScript for when user is logged in
</script>
<?php
} else {
?>
<script>
//Your JavaScript for when user is logged out
</script>
<?php
}
?>

    The plugin I used for the code insertion: Head, Footer and Post Injections plugin.


  2. 0

    All you need is an endpoint that will return 1 if the user is logged in, otherwise 0.

    let XHR = new XMLHttpRequest();
XHR.open( 'GET', '/yourEndPoint' );

XHR.onreadystatechange = function() {
   if (this.status == 200) {
       window.dataLayer = window.dataLayer || [];
       window.dataLayer.push({
           'userLoggedIn' : XHR.responseText
       });
       //Do something else here
   }
};

XHR.send();
    Login or Signup to reply.
  3. 0

    Echoing a FALSE in PHP doesn’t print anything to the screen. This is why your first example didn’t work and it produced invalid JS when the user wasn’t logged in.

    logintemp= ;

    A simple way to do this is to make sure you json_encode the server side data so the JS can access it. Since JSON is a subset of JS, it will properly escape any content and produce a valid expression that can be assigned to a variable.

    var isLoggedIn = <?php echo json_encode(is_user_logged_in()) ?>;

if (isLoggedIn) {
  window.dataLayer = window.dataLayer || [];
  window.dataLayer.push({
    'userLoggedIn': '1'
  });
} 
   
else {
   window.dataLayer = window.dataLayer || [];
   window.dataLayer.push({
     'userLoggedIn': '0'
   });
}

    And the above can be simplified to

    var isLoggedIn = <?php echo json_encode(is_user_logged_in()) ?>;
window.dataLayer = window.dataLayer || [];      
window.dataLayer.push({
   userLoggedIn: isLoggedIn ? '1' : '0'
});

    See Variable from html to javascript

    Generating JavaScript from PHP

    Dynamically generated code, as suggested by @Clarus Dignus, makes it much harder to read and maintain the code as you try to align code within both environments.

    Having a single place where all the server side data drives the code makes it a lot easier to debug the code since the JavaScript code itself is not changing, just a value.

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