Question 131337 in Xcode Question posted in
Whether you're new to Xcode or an experienced developer, our archive has everything you need to know about this integrated development environment (IDE). From basic functionalities to advanced features, our archive covers a wide range of Xcode-related questions and answers. Browse our archive now and find solutions to your Xcode questions, and take your app development skills to the next level

Xcode – change dictionary values to dictionaries from list of dictionaries in python

I have a list with 12 dictionaries, and the main dictionary with 12 keys. For every key in the main dictionary, I want to change the value to dictionary from the list of the dictionaries that I have. I have tried this but it doesn’t work:

values = []

for lst in href_lst:
    val = dict(Counter(lst))
    values.append(val)

for key in traffic_dict:
    for dict in values:
        traffic_dict[key] = dict

The output is that every key in the main dictionary has the same value. I need for every key a different value (different dictionary from the list).

Tags:

2

Answers


  1. 0

    This is because your second loop here

    for key in traffic_dict:
    for dict in values:
        traffic_dict[key] = dict

    is running even after assigning the value.
    This will assign the last value in the list "values" to every "key".

    Corrected code sample,

    i = 0
for key in traffic_dict:
    traffic_dict[key] = values[i]
    i += 1

    There can be multiple ways to do this. The above code is one of the ways.

    Login or Signup to reply.
  2. 0

    You could use a list comprehension and zip:

    values = [dict(Counter(lst)) for lst in href_lst]
for key, value in zip(traffic_dict, values):
    traffic_dict[key] = value

    Or, if you don’t need values later, just zip:

    for key, lst in zip(traffic_dict, href_lst):
    traffic_dict[key] = dict(Counter(lst))
    Login or Signup to reply.
Please signup or login to give your own answer.

Back To Top
Search