How can I create a predicate so that when the user selects "Full Body" it returns the entire list with no predicate? Right now, it is returning "part" which corresponds to the muscle groups I have set (Abs, Legs, Push, Pull). I want to return all of the options when "Full Body" is selected. How could I write an If statement so that the predicate is not used?
import SwiftUI
var parts = ["Abs", "Legs", "Push", "Pull", "Full Body"]
struct ExerciseList: View {
@State private var selectedPart = " "
var body: some View {
NavigationView {
VStack (alignment: .leading) {
NavigationLink(destination: AddExerciseView()){
Text("Add Exercise")
.fontWeight(.bold)
}
Picker("Body Part", selection: $selectedPart) {
ForEach(parts, id:.self) { part in
Text(part)
}
}.pickerStyle(.segmented)
ListView(part:selectedPart)
}
}
}
}
import SwiftUI
struct ListView: View {
var part: String
@FetchRequest var exercises: FetchedResults<Exercise>
init(part: String) {
self.part = part
self._exercises = FetchRequest(
entity: Exercise.entity(),
sortDescriptors: [],
predicate: NSPredicate(format: "musclegroup == %@", part as any CVarArg)
)
}
var body: some View {
List(exercises) { e in
Text(e.exercisename)
}
}
}
2
Answers
you could try this simple approach in
ListView
:It’s not a good idea to init objects inside View structs because the heap allocation slows things down. You could either have all the predicates created before hand or create one when the picker value changes, e.g. something like this:
Since you are using Core Data you might want to use an Int enum in the entity for less storage and faster queries.