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Xcode – SwiftUI – How to get access to "WindowScene"

In watching the WWDC 21 videos reference StoreKit 2, there are a few functions that they reference wherein they let a value = WindowScene as follows:

func manageSubscriptions() async {
    if let windowScene = self.view.window?.windowScene {
        do {
            try await AppStore.showManageSubscriptions(in: windowScene)
        } catch {
            //error
        }
    }
}

The let line errors out with the message: Type of expression is ambiguous without more context

If I try and provide more context with something like:

if let windowScene = (self.view.window?.windowScene)! as UIWindowScene {

I am told: Value of type 'MyStruct' has no member 'view'

What am I missing, must be something simple, to gain access to this needed UI element?

Thank you

Added:
I’d like to add that I am using a SwiftUI app that was created using a SceneDelegate and AppDelegate, not a simple struct: App, type of structure. So I am guessing I need to access something in the SceneDelegate to get the right object..

Tags:

2

Answers


  1. Chosen as BEST ANSWER
    0

    Just to provide an answer for anyone interested, with all credit to @aheze for finding it and @Matteo Pacini for the solution, to get this specific method to work when using a SwiftUI app that has an AppDelegate/SceneDelegate structure, this will work:

    @MainActor
func manageSubscriptions() async {
    if let windowScene = UIApplication.shared.connectedScenes.first {
        do {
            try await AppStore.showManageSubscriptions(in: windowScene as! UIWindowScene)
        } catch {
            //error
        }
    }
}

  2. 0

    You can conversely use the view modifier manageSubscriptionsSheet(isPresented:) instead. This is Apple’s recommended approach when using SwiftUI and will mitigate the need for getting a reference to the window scene.

    Source:

    If you’re using SwiftUI, call the manageSubscriptionsSheet(isPresented:)view modifier.

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