Question 19005 in Amazon Web Sevices Question posted in
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AWS cron expression to run a job every 2 days once – Amazon Web Sevices

I have a requirement to schedule a job in AWS CloudWatch events to be run once in every two days. I am using the below expression but getting a error Parameter ScheduleExpression is not valid

cron(0 0 */2 * ? *)

The below is the java code,

String cronExpression = "cron(0 0 */2 * ? *)"
    PutRuleRequest request = new PutRuleRequest();
        request
            .withName(eventName)
            .withRoleArn("arn:aws:iam::****")
            .withScheduleExpression(cronExpression)
            .withState(RuleState.ENABLED);
        PutRuleResult result = cloudwatchConfig.cloudwatch().putRule(request);
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2

Answers


  1. 0 
    cron(0 0 1/2 * ? *)

    You can verify here.

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  2. 0

    If you put your syntax into cloudwatch, it too will report the same error you are seeing in the terraform,but fix it simple

    cron(0 0 1-31/2 * ? *)

    The explanation for each field is here: https://docs.aws.amazon.com/AmazonCloudWatch/latest/events/ScheduledEvents.html

    1-31 covers all the possible number of days in a month

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