Question 285390 in Html Question posted in
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Html – Use Javascript to loop through an JSON object and return the indexes of the matching criteria

I have found this previous answer that semi-answers my question but I want to return an array of the indexes in which they appear – in this case ** 18A38** would return the location [1,3].

Entries are only an example – the final version would have potentially hundreds of entries.

const checkArray = ['18A38'] 

const dataOject =
  [ { id:'853K83', isGo:false }
  , { id:'18A38',  isGo:true  }
  , { id:'97T223', isGo:true  }
  , { id:'18A38',  isGo:false }
  , { id:'182B92', isGo:true  }
  ];

const result = checkArray.map(val=>dataOject.findIndex(el=>el.id===val) )


console.log( JSON.stringify(result))
Tags:

3

Answers


  1. 0

    Just loop through and push the indices you need onto an array

    const checkArray = ['18A38'] 

const dataOject =
  [ { id:'853K83', isGo:false }
  , { id:'18A38',  isGo:true  }
  , { id:'97T223', isGo:true  }
  , { id:'18A38',  isGo:false }
  , { id:'182B92', isGo:true  }
  ];
let foundIndices = []
for (let i = 0; i < dataOject.length; i++) {
   if (dataOject[i].id === checkArray[0]) {
      foundIndicies.push(i)
   }
}

return foundIndices
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  2. 0

    checkArray array is of length 1. Of course after using map you’d get only one value back.

    I’d do it that way:

    const checkArray = ['18A38'] 

const dataOject =
  [ { id:'853K83', isGo:false }
  , { id:'18A38',  isGo:true  }
  , { id:'97T223', isGo:true  }
  , { id:'18A38',  isGo:false }
  , { id:'182B92', isGo:true  }
  ];
  
  const result = dataOject.reduce((final, value, index) => {
    if (value.id === checkArray[0]) {
        return [...final, index];
    }

    return final;
  }, []);

  console.log(result);

    If potentially checkArray is of more values, you also could do:

    const checkArray = ['18A38', '853K83'] 

const dataOject =
  [ { id:'853K83', isGo:false }
  , { id:'18A38',  isGo:true  }
  , { id:'97T223', isGo:true  }
  , { id:'18A38',  isGo:false }
  , { id:'182B92', isGo:true  }
  ];
  
  const result = dataOject.reduce((final, value, index) => {
    if (checkArray.includes(value.id)) {
        return [...final, index];
    }

    return final;
  }, []);

  console.log(result);
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  3. 0

    You can use Array.reduce() to do this

    const checkArray = ['18A38'] 

const dataObject = [
  { id:'853K83', isGo:false },
  { id:'18A38',  isGo:true  },
  { id:'97T223', isGo:true  },
  { id:'18A38',  isGo:false },
  { id:'182B92', isGo:true  },
];

const result = dataObject.reduce((acc, val, i) => { 
  if (checkArray.includes(val.id)) {
    acc.push(i)
  }
  return acc;
}, [])


console.log( JSON.stringify(result))
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