Question 391755 in Javascript Question posted in
A very good W3school tutorial can be found here.

Javascript – How Can I Open All the Links at Once for My Search Query in Chrome or Any Other Browser?

Could you please help me with a problem? When I search for something on Google, I usually open all the links (about 10 or more) and then go through them one by one. I would like to enable a feature where all the query results (about 10 on the search page) open immediately in the same window.

If someone can help, it would be greatly appreciated.

If a custom script for tabs in the browser can achieve this, it would be ideal. However, I welcome any other suggestions or solutions.

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2

Answers


  1. Chosen as BEST ANSWER
    0

    add this script to the browser with the Tampermonkey extension and create a new script below.

    // ==UserScript==
// @name         Open Top Google Search Results
// @namespace    http://tampermonkey.net/
// @version      1.0
// @description  Automatically open top Google search results in new tabs
// @author       Your Name
// @match        https://www.google.com/search?*
// @grant        none
// ==/UserScript==

(function() {
    'use strict';

    const numResults = 10; // Number of top results to open

    function openLinks() {
        const resultLinks = document.querySelectorAll('a h3');
        let count = 0;

        for (let i = 0; i < resultLinks.length && count < numResults; i++) {
            const link = resultLinks[i].parentElement;
            const url = link.href;

            if (URL) {
                window.open(url, '_blank');
                count++;
            }
        }
    }

    window.onload = function() {
        setTimeout(openLinks, 3000); // Adjust delay if necessary
    };
})();

    Make sure to turn on Developer mode in the Chrome extension setting.


  2. 0

    You can create a snippet that will do that. First lets do a javascript code for the job:

    Let’s assume all links have ping attribute that starts with /url. Actually, it’s a little more complicated than that but I think this might work (as of today):

    document.querySelectorAll('#search a h3').forEach(function(h3) {
  /* if visible */
  if (h3.offsetParent !== null) {
    var a = h3.closest("a");
    var href = a.href;
    console.log(href);
  }
})

    And the result, after using https://mrcoles.com/bookmarklet/, can be found here https://jsfiddle.net/swhev0yk/

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