Question 89781 in PostgreSQL Question posted in
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How to do if elif statements in postgressql and save the outcome in a new column? – Postgresql

i’m quite new to postgressql, so i have a table called public.dim_products with a column called weight_kg
what i would like to do is given some weight in the weight ranges below to set up a new column called weight_class and have these values

`+--------------------------+-------------------+
 | weight_class VARCHAR(?)  | weight range(kg)  |
 +--------------------------+-------------------+
 | Light                    | < 2               |
 | Mid_Sized                | 3 - 40            |
 | Heavy                    | 41 - 140          |
 | Truck_Required           | > 141             |
 +----------------------------+-----------------+`

I’ve had a quick look at case statements and it seems to be what i’m after but when i do the statement it comes up with an error

sqlalchemy.exc.ProgrammingError: (psycopg2.errors.SyntaxError) syntax error at or near "CASE"

`SELECT weight_kg FROM public.dim_products
 CASE 
     WHEN weight_kg < 2 THEN Light
     WHEN weight_kg > 2 AND weight_kg < 41 THEN Mid_Sized
     WHEN weight_kg > 40 AND weight_kg <141 THEN HEAVY
     WHEN weight_kg > 140 THEN Truck_Required
 END weight_class;`

Ideally this shoul’ve created a column and had all these new mapping?

Using Kamran suggestion this is the corrected version of the syntax

dim_products_create_weight_class_col = """SELECT weight_kg,
 CASE 
     WHEN weight_kg::float < 2 THEN 'Light'
     WHEN weight_kg::float >= 2 AND weight_kg::float < 41 THEN 'Mid_Sized'
     WHEN weight_kg::float >= 41 AND weight_kg::float <141 THEN 'HEAVY'
     WHEN weight_kg::float >= 141 THEN 'Truck_Required'
 END AS weight_class
 FROM public.dim_products;

The issue is, it still didn’t create the weight_class column?

Tags:

2

Answers


  1. 0

    The syntax of your CASE expression is incorrect. Here’s a corrected version that follows the proper syntax:

    SELECT weight_kg, 
       CASE 
           WHEN weight_kg < 2 THEN 'Light'
           WHEN weight_kg >= 2 AND weight_kg < 41 THEN 'Mid_Sized'
           WHEN weight_kg >= 41 AND weight_kg < 141 THEN 'HEAVY'
           WHEN weight_kg >= 141 THEN 'Truck_Required'
       END AS weight_class
FROM public.dim_products;

    SELECT statement only retrieves the data. If you want to update an existing column, you may use following:

    UPDATE public.dim_products
SET weight_class = 
       CASE 
           WHEN weight_kg < 2 THEN 'Light'
           WHEN weight_kg >= 2 AND weight_kg < 41 THEN 'Mid_Sized'
           WHEN weight_kg >= 41 AND weight_kg < 141 THEN 'HEAVY'
           WHEN weight_kg >= 141 THEN 'Truck_Required'
       END;

    If weight_class column doesn’t exist, you can create with:

    ALTER TABLE public.dim_products
ADD COLUMN weight_class varchar(20);
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  2. 0

    Let’s assume that we start from the beginning:

    1. First of all – we are creating blank table

    CREATE TABLE weight_ranges_classes ( weight_class VARCHAR(30) , weight_range int4range,);

    (sorry for formatting)

    2. Below is a solution closely related to your scope

    a) Create table with ranges

    INSERT INTO weight_ranges_classes VALUES
('Light', '[, 2)'), 
('Mid_Sized', '[2, 40]'), 
('Heavy', '[41, 140]'), 
('Truck_Required', '[141,]') ;

    b) After that you can use ranges to select proper value

    select 
weight_class,
weight_range,
from 
weight_ranges_classes 
where 
--/ here you defining desired ranges of outcome query
'[2,5]'::intrange @>weight_range

    More information about ranges in postgres you cen found out here:
    https://www.youtube.com/watch?v=a2R9Vqd4x6o

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