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Global variable in javascript doesn't work as expected – Twitter-api

here is the code, I have a menu global variable inside the function. I want to use it outside it, but then I get an “undefined reference error…·
This is the only javascript code I have, so there’s no interference with another variables or functions.

Thanks in advance.

$(function() {
  menu =  $('nav#menu').mmenu(
    {   
      navbars: [
        {
          position: "top",  
          height    : 1,
          content : [ 
            '<a href="#/" class="fa fa-phone"></a>',
            '<img src="imagenes/wheel32.png" /><p class="navbartxt">bicimap.uy</p>',                    
          ]
        },
        {
          position: "bottom",
          content: [
            '<a class="fa fa-envelope"></a>',
            '<a class="fa fa-twitter"></a>',
            '<a class="fa fa-facebook"></a>'
          ]
        }
      ],                    
      extensions: ["multiline"],    
      onClick: {
        close: false
      },
      navbar:{
        title: "Inicio"                     
      },
      offCanvas: {           
        zposition : "next"
      }
    });         
  });

I need to put this inside the function to get it working

var API = $("#menu").data( "mmenu" );

menu.on( 'click', 'a[class^="fa fa-twitter"]', function() {  
  $('#twitter').show();                 
  var API = $("#menu").data( "mmenu" );
  API.close();      

  return false;
});
Tags:

3

Answers


  1. Chosen as BEST ANSWER
    0

    This is the solution I found, maybe it's not the best because it could bring problems. For some reason the ready function doesn't work as is shown above, maybe some assets are being expected.

    menu = null;
$(function() {

            menu =  $('nav#menu').mmenu(

            {   
                navbars     : [{
                    position: "top",    
                    height  : 1,
                    content : [ 

                        '<img src="imagenes/wheel32.png" /><p class="navbartxt">bicimap.uy</p>',                

                    ]
                },
                {
                    position: "bottom",
                    content: [
                        '<a class="fa fa-envelope"></a>',
                        '<a class="fa fa-twitter"></a>',
                        '<a class="fa fa-facebook"></a>'
                    ]
                }
                ],                  
                extensions: ["multiline"],  
                 onClick: {
                    close: false
                 },
                navbar:{
                    title: "Inicio"                     
                },
                offCanvas: {
                  zposition : "next"
                }

        });

    });


$( window ).load(function() {

  var API = $("#menu").data( "mmenu" );

        menu.on( 'click', 'a[class^="fa fa-twitter"]', function() {  
                        $('#twitter').show();

                          var API = $("#menu").data( "mmenu" );
                          API.close();      

                        return false;
                    }
         );

});

  2. 0

    I’m lacking some context here (I’m assuming there’s more we don’t see?)

    But you may be executing the latter snippet, menu.on( 'click'… before the code inside $(…) has run (on dom ready); so menu would be undefined.

    If you’re just getting started, it’s worth looking into your browser’s developer tools and learning about break points and logging.

    You’ll need to make sure that you use menu only after it’s been set, likely by delaying all your invocation to be on ready.

    Execution Order

    1. The $ is called and the function is provided as the first and only argument. The function itself is not called.

    2. API is defined by the result of $("#menu") This may or may not be found yet depending upon where in the html file you’ve added this script.

    3. The data method is invoked on the result of that

    4. You try to call on on menu, which is still undefined

    5. sometime later, the function you passed to $ is called, and menu ends up being defined, to late to be useful

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  3. 0

    If your closure/anonymous function is happening asynchonously, its possible that the work has not been done by the time the rest of your code is computed. I would need more context to determine that.

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