There are 4 user folders user1, user2, user3 and user4.
They all have music in their folder and I need to move these .mp4, .mkv and .mp3 files into the folder /tmp/Papierkorb
Also I need to rename it like, when user1 has a music file, it should change the name of the file into the name of the user_filename, from which user It comes from.
This is what I have now:
for file in $(find -type f -name *.mp3;find -type f -name *.mkv;find -type f -name *.mp4)
do
echo mv "$file" /tmp/Papierkorb$file;
done
This is what appears with echo:
root@ubuntu-VirtualBox:/home# bash script.sh
mv ./user2/music/hits.mp3 /tmp/Papierkorb./user2/music/hits.mp3
mv ./user4/hits/music.mp3 /tmp/Papierkorb./user4/hits/music.mp3
mv ./user1/lied1.mp3 /tmp/Papierkorb./user1/lied1.mp3
mv ./user1/lied1.mkv /tmp/Papierkorb./user1/lied1.mkv
mv ./user1/lied12.mp4 /tmp/Papierkorb./user1/lied12.mp4
mv ./user1/1lied12.mp4 /tmp/Papierkorb./user1/1lied12.mp4
mv ./user3/test/meinealben/testlied.mp4 /tmp/Papierkorb./user3/test/meinealben/testlied.mp4
When I remove the echo, it says, that the folder after Papierkorb doesn’t exist. I also don’t know anything how I rename it into the name of the user, from which user the file comes from.
2
Answers
With
find
you can group the-name
predicates and use the-exec ... {} +
construct:Notes:
find
per username-exec sh -c '...' "/tmp/Papierkorb/${user}_" {} +
is a little hackish but thanks to that you’ll directly have value of/tmp/Papierkorb/${user}_
as$0
in the inline scriptUsing find and awk
Using find and xargs