I’ve noticed that when using mix-blend-mode
the result is different than when using background-blend-mode
even though you’re using the same blending mode.
For example, compare the 2 results below:
I’ve copied in my setup and JSFiddles below:
HTML
<div class="background">
<div class="overlay"></div>
</div>
CSS
.background{
width:200px;
height:200px;
//background-color:green; //toggle depending on what you want to use
background-blend-mode:soft-light;
background-image:url('http://lorempixel.com/output/nightlife-q-c-640-480-2.jpg');
background-size:cover;
}
.overlay{
width:100%;
height:100%;
background-color:green; //toggle depending on what you want to use
mix-blend-mode:soft-light;
}
JSFiddle
Using mix-blend-mode: https://jsfiddle.net/p8gkna87/
Using background-blend-mode: https://jsfiddle.net/p8gkna87/1/
Some background information
I’m currently replicating a photoshop design which uses the soft-light blending mode and at the same time also uses an opacity of 51%. So it wouldn’t be able to use background-blend-mode
as the opacity cannot be applied to the same object.
3
Answers
it looks like to me that
mix-blend-mode
also usesbackground-color
to blend it whenbackground-blend-mode
doesn’t.test using and change
background-color
as well:http://www.w3schools.com/cssref/tryit.asp?filename=trycss_background-blend-mode
background-blend-mode
blends with itsbackground-image
and itsbackground-color
.mix-blend-mode
blends with its backdrop, the part what is behind itself, and itsbackground-color
.Here is an article describing
mix-blend-mode
quite well:Put in another way, and in your case, with your
mix-blend-mode
you blend a green color on top of the image, with yourbackground-blend-mode
you do the opposite.So by having the same layer order, both
blend-modes
look the sameYou have already a good answer from LGSon.
Just to clarify it a little bit further:
The layers that you have here are, from botton to top:
The background-blendmode applies inside the background element, in this case layer 2 over layer 1
The mix-blend-mode applies element 3 over the result of 1 + 2
So, if only one of them is efffective, the order is the inverse